Jun. 12th, 2007

jack: (Default)
I killed a buzzing thing. It was mortally wounded and flying in little circles on the surface of the table, so I felt I had to put it out of its misery, but I don't want to kill anything. OK, buzzing things about a millimetre across feel like they don't count, but illogically being about a centimetre feels over some threshold.

Maybe my career as a vampire slayer is not ordained. Though I don't know, vampires known to be evil come in the same category as plague-carrying mosquitoes, "Sorry bub, but its you or me."

Bridge

Jun. 12th, 2007 12:38 am
jack: (Default)
*Last* time I played bridge it was all 4443, 4443, 4432, 4443, 4443, every hand making me go "OK, now how do you bid to an uncontested partial score again?"

*This* time, 55s and 67s and other crazy shit singleton beer cards[1] abounded. I arrived to witness J play four consecutive hands, the last three with 4-0 or 5-0 trump splits against. *Several* hands with no notable feature other than a spade straight[1]. But it was fun and instructive, as always.

[1] The beer card is the 7 of diamonds. A spade straight is 356789 or similar. Neither has any importance for the play of the game, except if you find your life insufficiently illuminated by bidding conventions.
jack: (Default)
1. You could eliminate the rolling problem on a d7 by using a sphere and painting seven equal areas on the surface (in an appropriately semi-symmetric non-striped way). The only flaw being it not ending on one certain face.

2. You could do that, but have a heptahedral die with little airbags that expands into a sphere for rolling, and then you collapse remotely causing it to fall on one face. But that's over-engineered.

3. ptc suggests the question with the d0 is you're looking at external faces, which should be the only ones that count. If you have a gigantic cube surrounding the earth, that could be a d0. Though rolling it is dangerous.

4. What is the generalisation of a dn for n not positive? Consider Euler's formula. Define D=2+E-V, where E=number of edges and V=number of vertices. For simply connected solids, eg. polyhedrons, D=F. Aha, we're onto a concept we can generalise. For D is also defined for other shapes†. A torus divided into n has D=n+2 which isn't very helpful‡. However, two spheres with n total regions has D=n-2.

So if n is two, (eg. Each sphere consists of a single vertex and single face, and no edges -- I think this isn't pathological by euler characteristic standards), D=0 as desired.

Except this isn't very vivid. I can show you two marbles and say "Lo! These two marbles are a no-sided die" and probably be a hit at Buddhist drug raves, but it doesn't actually illuminate the problem very helpfully, or suggest interesting further maths/engineering to do :)

† Use the Euler Characteristic, explanations tomorrow. In short, V-E+F=Chi, where Chi is defined topologically. Polyhedrons are all topologically equivalent to a sphere, and Chi is two. Donuts and holed solids have Chi=2-2g where g is the genus is number of holes. Two spheres have Chi=4, as you can see by adding up V, E, F and getting 2 for each.

‡ Except maybe to act as a warning bell that our generalisation may be starting to come apart at the seams already. In what sense is a torus havign seven regions equivalent to a d9?

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