Mathematical humour

[jack]

Simont: Is there a set of players each of whom plays a single win-or-lose game against each other player, where every pair of players has a third player who beat both?
Jack: *thinks*
Jack: Yes.
Simont: Not that one.

Comments

[simont]

There's a trivial answer, which is to let the set have fewer than 2 players. Then "every pair" has a third player who beats both, in the vacuous sense that you can't exhibit a pair for which this condition fails.